S SieghartZeke Member Member Joined Oct 4, 2009 Messages 149 Points 0 Age 29 Mysidian Dollar 6,621 Oct 10, 2009 #1 Someone know how to add in the profile page a feature that you can show the name of the other adoptable?
Someone know how to add in the profile page a feature that you can show the name of the other adoptable?
X Xius Member Member Joined Apr 13, 2009 Messages 59 Points 0 Mysidian Dollar 4,853 Oct 10, 2009 #2 Something like this? http://pokemonepiphany.com/pokepals/levelup.php?id=90
S SieghartZeke Member Member Joined Oct 4, 2009 Messages 149 Points 0 Age 29 Mysidian Dollar 6,621 Oct 10, 2009 #3 Yes...
X Xius Member Member Joined Apr 13, 2009 Messages 59 Points 0 Mysidian Dollar 4,853 Oct 10, 2009 #4 Just use the ".$name." variable!
S SieghartZeke Member Member Joined Oct 4, 2009 Messages 149 Points 0 Age 29 Mysidian Dollar 6,621 Oct 11, 2009 #5 Ehm....where???
X Xius Member Member Joined Apr 13, 2009 Messages 59 Points 0 Mysidian Dollar 4,853 Oct 11, 2009 #6 Wherever you want, you just have to pull it from the database first, and most pages already do that.
G gabeki Premium Member Premium Member Joined Oct 1, 2009 Messages 24 Points 0 Mysidian Dollar 0 Oct 11, 2009 #7 Really? I can just put $name? O: I did this: PHP: function getcurrentname($id){ include("config.php"); $query = "SELECT * FROM ".$prefix."owned_adoptables WHERE aid='$id'"; $result = mysql_query($query); $num = mysql_numrows($result); //Loop out code $i=0; while ($i < 1) { $currentname=@mysql_result($result,$i,"name"); $i++; } return $currentname; } added that to function.php and this to every page I wanted to show the name: PHP: $query = "SELECT * FROM ".$prefix."owned_adoptables WHERE owner = '".$user."'"; $aid=@mysql_result($result,$i,"aid"); $nameofpet = getcurrentname($aid); and then I use $nameofpet, to show the name I'm so dumb D:
Really? I can just put $name? O: I did this: PHP: function getcurrentname($id){ include("config.php"); $query = "SELECT * FROM ".$prefix."owned_adoptables WHERE aid='$id'"; $result = mysql_query($query); $num = mysql_numrows($result); //Loop out code $i=0; while ($i < 1) { $currentname=@mysql_result($result,$i,"name"); $i++; } return $currentname; } added that to function.php and this to every page I wanted to show the name: PHP: $query = "SELECT * FROM ".$prefix."owned_adoptables WHERE owner = '".$user."'"; $aid=@mysql_result($result,$i,"aid"); $nameofpet = getcurrentname($aid); and then I use $nameofpet, to show the name I'm so dumb D:
X Xius Member Member Joined Apr 13, 2009 Messages 59 Points 0 Mysidian Dollar 4,853 Oct 11, 2009 #8 Yeah. xD PHP: //The adoptable's ID $aid = @mysql_result($result, $i, "aid"); $currentlevel = @mysql_result($result, $i, "currentlevel"); $type = @mysql_result($result, $i, "type"); $name = @mysql_result($result, $i, "name"); That's just an example of what it is in the myadopts.php page. Just pull the name from the database.
Yeah. xD PHP: //The adoptable's ID $aid = @mysql_result($result, $i, "aid"); $currentlevel = @mysql_result($result, $i, "currentlevel"); $type = @mysql_result($result, $i, "type"); $name = @mysql_result($result, $i, "name"); That's just an example of what it is in the myadopts.php page. Just pull the name from the database.
S SieghartZeke Member Member Joined Oct 4, 2009 Messages 149 Points 0 Age 29 Mysidian Dollar 6,621 Oct 11, 2009 #9 But...when i add $name i cant show the name of my chaarcter in myadopt page!
X Xius Member Member Joined Apr 13, 2009 Messages 59 Points 0 Mysidian Dollar 4,853 Oct 11, 2009 #10 You have to include the whole thing - PHP: ".$name."
S SieghartZeke Member Member Joined Oct 4, 2009 Messages 149 Points 0 Age 29 Mysidian Dollar 6,621 Oct 12, 2009 #11 AHH....BUT I GET SOME DISASTER WHEN I ADD!I SO NOOB!